python 下xml和dict相互转化，含attributes -

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python 下xml和dict相互转化，含attributes

from lxml import etree
def dictlist(node): res = {} res[node.tag] = [] xmltodict(node,res[node.tag]) reply = {} reply[node.tag] = {'value':res[node.tag],'attributes':node.attrib} return reply
def xmltodict(node,res): rep = {} if len(node): #n = 0 for n in list(node): rep[node.tag] = [] value = xmltodict(n,rep[node.tag]) if len(n): value = {'value':rep[node.tag],'attributes':n.attrib} #print value res.append({n.tag:value}) else : #print rep[node.tag][0] res.append(rep[node.tag][0]) else: value = {} value = {'value':node.text,'attributes':node.attrib} #print value res.append({node.tag:value}) return def fromstring(strdict=None): root = etree.fromstring(strdict) return dictlist(root)
def parse(filename=None): tree = etree.parse(filename) return dictlist(tree.getroot()) 
def main(): tree = etree.parse('test.xml') print tree res = dictlist(tree.getroot()) print res def dict2xml(d): from xml.sax.saxutils import escape def unicodify(o): if o is None: return u''; return unicode(o) lines = ["<?xml version=/"1.0/" encoding=/"utf-8/"?>"] def addDict(node, offset): for name, value in node.iteritems(): if name == "attributes": strqq = lines[len(lines)-1] index = strqq.find(u"<") strqq = strqq[index+1:len(strqq)-1] for x,y in value.iteritems(): strqq = strqq + u" " *4 + u"%s='%s'"%(x,y) lines[len(lines)-1] = u" " * index + u"<%s>"%(strqq) else: if isinstance(value, dict): lines.append(offset + u"<%s>" % name) addDict(value, offset + u" " * 4) lines.append(offset + u"</%s>" % name) elif isinstance(value, list): for item in value: if isinstance(item, dict): addDict(item, offset + u" " * 4) else: lines.append(offset + u"<%s>%s</%s>" % (name, escape(unicodify(item)), name)) else: if value != "": pass addDict(d, u"") lines.append(u"") return u"/n".join(lines) #if __name__ == '__main__' : #main()
test 就不帮大家写了

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